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Resonance

The key idea

A capacitor bank and the network's inductance form a tuned circuit. At one frequency — the resonant frequency — they trade energy back and forth and the bus impedance spikes. If that spike lands on a harmonic order your loads inject, small currents make big voltage distortion.

The idea

Capacitor banks are installed for good reasons: they supply reactive power locally and prop up the voltage. But a capacitor next to an inductive network is never just a capacitor — together they make a resonant pair, like a mass on a spring.

Seen from the bus, the two sit in parallel. At most frequencies one or the other dominates and the combined impedance stays low. But at the frequency where their reactances are equal, they form a parallel resonance: current circulates between the capacitor and the inductance, and to anything injecting current at that frequency, the bus looks like an enormous impedance.

Voltage distortion is injected current × bus impedance. So the question is never whether there is a resonance — with a capacitor bank installed, there always is one — but where it sits. The resonant order follows a usefully simple rule: h ≈ √(fault level ÷ bank size). Bigger banks tune the resonance lower, down toward the 7th and 5th — exactly where six-pulse drives inject.

Try it

Resize the bank and walk the peak across the injection orders.

Steer the resonance

resonance near order 7.1 (354 Hz)

0.1 pu1 pu10 pu100 pu15101520harmonic order →5th7th11th13th
5.0 Mvar on a 250 MVA bus

The peak sits on the 7th. Six-pulse drives inject exactly there. Whatever 7th-harmonic current flows into this bus meets a huge impedance — and voltage distortion is current × impedance. Resize the bank, or detune it with a reactor, to move the peak off the order.

Why it matters

  • This is how mild networks go bad overnight. Nothing changed but a new capacitor bank — and the 7th-harmonic voltage triples. The injected currents were always there; the bank moved the amplifier onto them.
  • The frequency scan needs no load data at all. The resonance is a property of the network itself. A scan tells you where the peaks sit before a single harmonic source is modeled — the cheapest useful harmonic result there is.
  • The fix is tuning, not removal. A detuning reactor in series with the bank shifts the resonance to a safe frequency (and the bank still does its reactive-power job). But a filter that fixes one order can create a new resonance at another — always re-run the scan after the fix.
The math, if you want itOptional — the page reads completely without it

Parallel resonance occurs where the two reactances are equal:

the resonance condition

h · Xs = Xch

the resonant order

hres = √( XcXs ) = √( SscQc )

with Ssc the fault level and Qc the bank rating. A 5 Mvar bank on a 250 MVA bus resonates near h = √50 ≈ 7.1 — on top of the 7th. The height of the peak is set by the network's losses: low resistance, tall peak.

See it in Phasor

Phasor's frequency scan sweeps the driving-point impedance at each bus across the harmonic orders and ranks the resonance candidates it finds — before you enter any load spectra. Test the detuned bank in the model and scan again.

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